Test Index

GATE Mechanical Engineering (ME) 2022 Shift 1 Solved Paper

© examsnet.com

Question : 43 of 65

Marks: +1, -0

A solid spherical bead of lead (uniform density = 11000 kg/m³) of diameter d = 0.1 mm sinks with a constant velocity V in a large stagnant pool of a liquid (dynamic viscosity = 1.1 × 10^-3 kg∙m^-1∙s^-1). The coefficient of drag is given by

C_{D} = \frac{24}{Re}

, where the Reynolds number (Re) is defined on the basis of the diameter of the bead. The drag force acting on the bead is expressed as

D = (C_{D})(0.5\rho V^{2}) \left( \frac{\pi d^{2}}{4} \right) ,

where ρ is the density of the liquid. Neglect the buoyancy force. Using g = 10 m/s², the velocity V is __________ m/s.

$\frac{1}{24}$
$\frac{1}{6}$
$\frac{1}{18}$
$\frac{1}{12}$

Go to Question:

Prev Question

Next Question