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GUJCET 2018 Chemistry Solved Paper
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© examsnet.com
Question : 10
Total: 40
At 27º C temperature, time required for 75% completion of a first order reaction is 20 seconds. What will be its rate constant?
0.693
s
e
c
–
1
m
o
l
e
–
1
lt
0.0693
s
e
c
–
1
0.693
s
e
c
–
1
0.0693
s
e
c
–
1
m
o
l
e
–
1
lt
Validate
Solution:
For 1^{st} order Reaction :
K
=
1
t
l
n
Co
Ct
at 75% completion : Ct= 25%
K
=
2.303
20
log
100
25
:
k
=
0.0697
s
e
c
−
1
© examsnet.com
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