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GUJCET 2018 Physics Solved Paper
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© examsnet.com
Question : 28
Total: 41
The value of β of a transistor is 19. The value of α will be
0.93
0.98
0.99
0.95
Validate
Solution:
I
E
=
I
B
+
I
C
⇒
I
E
I
C
=
I
B
I
C
+
1
⇒
1
α
=
1
β
+
1
=
1
19
+
1
⇒
1
α
=
20
19
⇒
α
=
19
20
=
0.95
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