10x+2y−11z=3 Here the direction ratios of the line =(2,3,6) Direction ratios of the normal to plane =(10,2,−11) Angle between the line and the plane can be written as sin−1(
a×a′+b×b′+c×c′
√a2+b2+c2√a′2+b′2+c′2
) Where (a,b,c) are the direction ratios of a line and (a′,b′,c′) are the direction ratios of the normal to the plane Substituting the values =sin−1(