GUJCET 2024 Chemistry Paper

Concept:Hybridization depends on the geometry and ligand field strength of the complex.Explanation:In $[\mathrm{Ni}(\mathrm{CO})_4]$, Ni is in zero oxidation state and the complex is tetrahedral. Tetrahedral geometry corresponds to $sp^3$ hybridization. In $[\mathrm{Ni}(\mathrm{CN})_4]^{2-}$, Ni is in $+2$ oxidation state and $\mathrm{CN}^{-}$ is a strong field ligand. Strong field ligands cause pairing of electrons and the complex becomes square planar. Square planar geometry corresponds to $dsp^2$ hybridization.Answer:$sp^3$ and $dsp^2$