In acidic solution, MnO₄²-} converts into . . . . . . .

Correct Answer is : MnO4−MnO₄^-MnO4− and MnO2MnO₂MnO2

Correct Answer is : MnO4−MnO₄^-MnO4− and MnO2MnO₂MnO2

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GUJCET 2025 Chemistry Paper

Question : 1 of 40

Marks: +1, -0

MnO_4^{2-}

converts into . . . . . . .

Solution:

Concept:

In acidic medium, manganate ion undergoes disproportionation.

Explanation:

\mathrm{MnO}_4^{2-}

is unstable in acidic solution.

It disproportionates into permanganate ion and manganese dioxide.

Balanced reaction:

3\mathrm{MnO}_4^{2-} + 4\mathrm{H}^+ \rightarrow 2\mathrm{MnO}_4^- + \mathrm{MnO}_2 + 2\mathrm{H}_2\mathrm{O}

Thus, the products are

\mathrm{MnO}_4^-

and

\mathrm{MnO}_2

Answer:

Option A:

\mathrm{MnO}_4^-

and

\mathrm{MnO}_2

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