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GUJCET 2026 Math Paper

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Question : 9 of 40

Marks: +1, -0

The total revenue in Rupees received from the sale of

x

units of a product is given by

R(x) = 3x^2 + 36x + 5

. The marginal revenue, when

x = 15

is . . . . . . .

$96$
$116$
$90$
$126$

Solution:

Concept:

Marginal revenue is the derivative of the total revenue function with respect to

x

.

Explanation:

Given

R(x) = 3x^2 + 36x + 5

.

Differentiate

R(x)

to get marginal revenue:

MR = \frac{dR}{dx} = 6x + 36

Substitute

x = 15

:

MR = 6(15) + 36

MR = 90 + 36 = 126

Answer:

The marginal revenue when

x = 15

is

126

.

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