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Haryana Police Constable Model Paper 4

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Question : 5 of 100

Marks: +1, -0

HCF of

\frac{9}{10},\frac{3}{25}

is:

$50$
$\frac{1}{150}$
$\frac{3}{50}$
$\frac{3}{150}$

Solution:

Given:

We have to find the HCF of

\frac{9}{10},\frac{3}{25}

Concept Used:

HCF of fraction =

\frac{\text{HCF of numerator}}{\text{LCM of denominator}}

Calculation:

HCF of

\frac{9}{10},\frac{3}{25}

⇒

\frac{\text{HCF (9, 3)}}{\text{LCM (10, 25)}}

HCF of numerators is 3

LCM of denominators is 50

Required HCF is

\frac{3}{50}

∴ HCF of

\frac{9}{10},\frac{3}{25},\frac{6}{15},\frac{1}{25} \text{ is } \left(\frac{3}{50}\right).

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