According to the given information abxy α c2z ⇒ abxy = c2z ...(i) bx β ay ⇒ bx > ay ...(ii) and b2 α ac ⇒ b2 = ac ...(iii) From (ii), we get b2x > bay ⇒ acx > bay [∴ b2 = ac from (iii)] ⇒ cx > by ...(iv) From (i), we get by = axc2z Putting (v) in (iv), we get cx = axc2z ⇒ ax2 > cz ⇒ ax2 β cz.