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IBPS Clerk Prelims Model Paper 3

Question : 5 of 100

Marks: +1, -0

\frac{(3.537-0.948)^2+(3.537+0.948)^2}{(3.537)^2+(0.948)^2}

= ?

Solution:

Concept:

Use algebraic identities to simplify the expression without direct calculation.

Explanation:

Let

a=3.537

and

b=0.948

The given expression becomes

\frac{(a-b)^2+(a+b)^2}{a^2+b^2}

Expand the numerator:

(a-b)^2+(a+b)^2=(a^2-2ab+b^2)+(a^2+2ab+b^2)

The terms

-2ab

and

+2ab

cancel, giving

2a^2+2b^2=2(a^2+b^2)

So the expression becomes

\frac{2(a^2+b^2)}{a^2+b^2}

Cancel

a^2+b^2

from numerator and denominator.

The result is

2

Answer:

2

(Option D).

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