IBPS PO Mains 12 Oct 2025 Shift 1 Paper

Concept:Use the positional clues to reduce the possible arrangements and find the only meaningful word.Explanation:Let the seven positions be numbered 1 to 7 from the left.Since either B or R is at the left end and exactly two letters are placed between them:Case 1: $B \ \_ \ \_ \ R \ \_ \ \_ \ \_$Case 2: $R \ \_ \ \_ \ B \ \_ \ \_ \ \_$I is immediately right of R:Case 1: $B \ \_ \ \_ \ R \ I \ \_ \ \_$Case 2: $R \ I \ \_ \ B \ \_ \ \_ \ \_$Let E be at position $p$ and N at position $q$.Letters to the left of E equal letters to the right of N, so $p - 1 = 7 - q$, giving $p + q = 8$.G is immediately right of N, so N and G must be adjacent with N before G.E is immediately left of A, so E and A must be adjacent with E before A.In Case 2, the remaining positions do not allow both adjacent pairs to fit.So Case 2 is eliminated.In Case 1, the valid arrangements are:$B \ E \ A \ R \ I \ N \ G$ = BEARING$B \ N \ G \ R \ I \ E \ A$ = not a meaningful wordOnly the word BEARING is meaningful.The fourth letter from the left end of BEARING is R.Answer:$R$