IBPS PO Mains 30 Nov 2024 Shift 2 Paper

Concept:Simple interest amount is given by $\text{Amount} = \text{Principal} \times \left(1 + \frac{\text{Rate} \times \text{Time}}{100}\right)$.Explanation:For Scheme A, principal is Rs. $(P+700)$, rate is $12\%$ p.a., and time is 15 years.So, total interest percentage is $12 \times 15 = 180\%$.Therefore, amount becomes $100\% + 180\% = 280\%$ of the principal.So, $2.8(P+700) = 4P - 200$.Solving: $2.8P + 1960 = 4P - 200$$1.2P = 2160$$P = 1800$.For the second sum, principal is Rs. $(M+300)$, rate is $12\%$ p.a., and time is 10 years.Total interest percentage is $12 \times 10 = 120\%$.So, amount becomes $100\% + 120\% = 220\%$ of the principal.Thus, $2.2(M+300) = 3P + 1200$.Substitute $P = 1800$: $2.2(M+300) = 3(1800) + 1200 = 6600$$M + 300 = 3000$$M = 2700$.Now check the statements:Statement I: $P = 2M$ gives $1800 = 2(2700) = 5400$, which is false.Statement II: $P + M = 2(M - 450)$ gives $1800 + 2700 = 2(2700 - 450)$, i.e. $4500 = 4500$, which is true.Statement III: HCF of $1800$ and $2700$ is $900$, not $180$, so this statement is false.Answer:Only statements I and III are not true.Hence, the correct option is B.