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IBPS PO Mains 5 Nov 2023 Paper

Question Numbers: 153-154

Directions: Answer the questions based on the information given below.

In the following question, two missing number series I and II are given.

Series I: 808, 520, 352, 232, A, 160

Series II: 500, 260, 140, 100, B, 88

Question : 153 of 155

Marks: +1, -0

Find the average of value of B, B + 12, and B + 36.

Solution:

Concept:

Use the given number series to find

B

, then calculate the average of

B

B+12

, and

B+36

Explanation:

Consider the series

500, 260, 140, 100, B, 88

Subtract consecutive terms to get differences:

500-260=240

260-140=120

140-100=40

These differences follow the pattern of dividing by

2, 3, 4, 5

240 \div 2 = 120

120 \div 3 = 40

40 \div 4 = 10

10 \div 5 = 2

So,

100 - B = 10

, which gives

B = 90

Check:

B - 88 = 90 - 88 = 2

, which matches the pattern.

Now compute the average:

\frac{B + (B+12) + (B+36)}{3} = \frac{90 + 102 + 126}{3}

= \frac{318}{3} = 106

Answer:

106

(Option A)

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