IBPS PO Prelims 23 Aug 2025 Shift 3 Solved Paper

Concept:First find the number of boys in Class A and Class D from the given girl counts and boy:girl ratios.Then apply the given percentage transfers and compute the new totals to find the required ratio.Explanation:For Class A, $B : G = 6 : 5$ and Girls $= 45$.So $5$ parts $= 45$, hence $1$ part $= 9$.Boys in Class A $= 6 \times 9 = 54$.For Class D, $B : G = 7 : 4$ and Girls $= 32$.So $4$ parts $= 32$, hence $1$ part $= 8$.Boys in Class D $= 7 \times 8 = 56$.Now, $55.55\% = \frac{5}{9}$.Boys shifting from A to D $= \frac{5}{9} \times 54 = 30$.Girls shifting from D to A $= 25\%$ of $32 = 8$.New total in Class A $= (54 - 30) + (45 + 8) = 24 + 53 = 77$.New total in Class D $= (56 + 30) + (32 - 8) = 86 + 24 = 110$.Required ratio $= 77 : 110$.Simplifying by dividing both terms by $11$, we get $7 : 10$.Answer:$7 : 10$ (Option D)