IBPS PO Prelims 24 Aug 2025 Shift 1 Solved Paper

Concept:This is a floor-and-flat arrangement puzzle solved by fixing direct positions and eliminating invalid cases.Explanation:Each floor has two flats: Flat-$1$ (west) and Flat-$2$ (east).Since no one lives to the west of C, C must be in Flat-$1$.C lives on an odd-numbered floor, and A lives exactly one floor above C in the same flat, so two cases arise.Case 1: C is on floor $1$ and A is on floor $2$; Case 2: C is on floor $3$ and A is on floor $4$.There are two floors between G and R, and R is below G, so G is on floor $4$ and R is on floor $1$.In Case 2, the person one floor below H would force P onto floor $1$ or make H equal to A or C, so Case 2 is eliminated.In Case 1, R is placed in Flat-$2$ on floor $1$, and G is placed on floor $4$.Applying clue 6, the person exactly one floor below H in the same flat occupies Flat-$1$ on floor $3$.Hence H is on floor $4$ Flat-$1$, and P, living to the east, is on floor $3$ Flat-$2$.Since J and R are not in the same numbered flat, J takes Flat-$1$ on floor $3$.The remaining person T takes Flat-$2$ on floor $2$.Final arrangement: Floor $4$: H, G; Floor $3$: J, P; Floor $2$: A, T; Floor $1$: C, R.So A and T live together on floor $2$.Answer:Option C: A and T