IBPS RRB PO Prelims 22 Nov 2025 Shift 2 Paper

Concept:Arrange the seven persons from heaviest to lightest using the given weight comparisons.Formula:If a person is heavier than exactly $n$ persons, then exactly $n$ persons are lighter than them.Solution:Positions are from heaviest ($1$) to lightest ($7$).$E$ is second lightest $\Rightarrow E=6$.$G$ is heavier than exactly three persons $\Rightarrow G=4$.$A$ is heavier than only two persons $\Rightarrow A=5$.$F$ is lighter than only two persons $\Rightarrow F=3$.Given $D > C > F$.So $D$ and $C$ must occupy positions $1$ and $2$, with $D > C$.Thus $D=1$ and $C=2$.Remaining $B$ goes to position $7$.Final order: $D > C > F > G > A > E > B$.Hence $D$ is the heaviest.Answer:D. D