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IBPS RRB PO Prelims 22 Nov 2025 Shift 2 Paper

Question Numbers: 1-5

Directions: Read the information carefully and answer the given questions.

Eight persons, namely, A, B, C, D, E, F, G, and H, were born in different years chosen from 1957, 1966, 1975, 1984, 1993, 1999, 2004, 2010, but not necessarily in the same order. All of them were born on the same date (day & month) of different years. All the age calculations below use the base year 2025.

E×actly two persons were born between B and C. Neither A nor F was born in 2010. The number of persons born after A is the same as the number of persons born before H. F was born immediately after A. The sum of the ages of D and E is 73. There is a 9-year gap between the years in which C and D were born.

Section: Reasoning

Question : 3 of 80

Marks: +1, -0

How many persons were born between C and H?

None
One
Two
Three
Four

Validate

Solution:

Concept:

Use the given clues to arrange all persons by their birth years.

Then count the number of persons between

C

and

H

Formula:

\text{Age} = 2025 - \text{Birth Year}

Solution:

Sum of ages of

D

and

E

73

, so

D

and

E

are born in

1984

and

1993

The

9

-year gap between

C

and

D

gives

C

1975

Exactly two persons between

B

and

C

places

B

1999

F

immediately after

A

and neither in

2010

gives

A

1957

and

F

1966

Equal persons after

A

and before

H

places

H

2010

Remaining

G

is in

2004

Final order (earliest to latest):

1957

A

1966

F

1975

C

1984

D

1993

E

1999

B

2004

G

2010

H

Persons between

C

(

1975

) and

H

(

2010

) are

D

E

B

, and

G

Number of persons =

4

Answer:

Option E: Four.

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