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IBPS RRBs Officer Scale I and II 13 Sep 2015 Paper
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© examsnet.com
Question : 57
Total: 200
I.
x
2
–
4
x
–
12
=
0
II.
y
2
–
5
y
–
14
=
0
1
2
3
4
5
Validate
Solution:
(4)
I.
x
2
–
4
x
–
12
=
0
⇒
x
2
–
6
x
+
2
x
–
12
=
0
⇒ x(x – 6) + 2 (x – 6) = 0
⇒ (x + 2) (x – 6) = 0
⇒ x = –2 or, 6
II.
y
2
–
5
y
–
14
=
0
⇒
y
2
–
7
y
+
2
y
–
14
=
0
⇒ y (y – 7) + 2 (y – 7) = 0
⇒ (y – 7) (y + 2) = 0
⇒ y = 7 or, –2
Clearly, x ≤ y
© examsnet.com
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