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IBPS SO Prelims Exam Model Paper 8
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© examsnet.com
Question : 119
Total: 150
Three numbers are in arithmetic progression such that the ratio of first number and third number is 1 ∶ 3 and second number is 1000, then find the first number?
500
300
200
2000
700
Validate
Solution:
Let the three numbers are a, a + d and a + 2d, where d is the common difference.
⇒ a ∶ (a + 2d) = 1 ∶ 3
⇒ 3a = a + 2d
⇒ 2a = 2d
⇒ a = d
Now the second number is 1000
⇒ a + d = 1000
⇒ a + a = 1000
⇒ 2a = 1000
⇒ a = 500
∴ The first number is 500
© examsnet.com
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