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IIT JEE Advanced 2006 Paper 1
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© examsnet.com
Question : 10
Total: 120
A student performs an experiment for determination of g
(
=
4
π
2
l
T
2
)
, l = 1 m, and he commits an error of Δl. For T, he takes the time of n oscillations with the stop watch of least count ΔT and he commits a human error of 0.1 s. For which of the following data, the measurement of g will be most accurate?
Δl = 5 mm; ΔT = 0.2 s; n = 10; A = 5 mm.
Δl = 5 mm; ΔT = 0.2 s; n = 20; A = 5 mm.
Δl = 5 mm; ΔT = 0.1 s; n = 20; A = 1 mm.
Δl = 1 mm; ΔT = 0.1 s; n = 50; A = 1 mm.
Validate
Solution:
We have
g =
4
π
2
l
T
2
Therefore,
Δ
g
g
=
Δ
l
l
+
2
Δ
T
T
Since Δl = 1 mm and ΔT = 0.1 s are least of the four given set of data and the number of oscillations observed is maximum (n = 50), g is most accurate with minimum amplitude (1 mm).
© examsnet.com
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