sin2ωt • For A = −B; C = 2B: x = Bcos2ωt + Bsin2ωt which is a SHM whose amplitude is B √2. • For A = B, C = 0, we get x = A, which is not a SHM. • For A = B, C = 2B: x = B + Bsin2ωt which is SHM whose amplitude is B. • For any values of A, B and C (except C = 0) x =