We see the following: • FBC is perpendicular plane of the loop and it acts in the upward direction. • FDA is perpendicular of the loop and it acts in the downward direction. Therefore, the net force on the loop is zero. FAB = FCD = 0 Now ,
→
J
= I
→
A
×
→
B
|
→
J
| = IAB sin θ Here , θ = 90° , |
→
J
| = IAB ≠ 0. As seen from the point O, the loop rotates in clockwise direction.