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IIT JEE Advanced 2006 Paper 1
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© examsnet.com
Question : 2
Total: 120
Two blocks A and B of masses 2m and m, respectively, are connected by a massless and inextensible string. The whole system is suspended by a massless spring as shown in the figure. The magnitudes of acceleration of A and B, immediately after the string is cut are, respectively,
g, g/2
g/2, g
g, g
g/2, g/2
Validate
Solution:
For block A: We have
T
2
=
T
1
+
2
m
g
Therefore,
T
2
= 3mg.
For block B: We have
When the string is cut,
T
1
= 0. Therefore, for block B,
mg =
m
a
B
⇒
a
B
= g
and for block A,
3mg – 2mg =
2
m
a
A
⇒
a
A
=
g
2
© examsnet.com
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