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IIT JEE Advanced 2006 Paper 1
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© examsnet.com
Question : 73
Total: 120
75.2 g of
C
6
H
5
O
H
(phenol) is dissolved in a solvent of
K
f
= 14. If the depression in freezing point is 7 K then find the percentage of phenol that dimerises.
Your Answer:
Validate
Solution:
The dimerization reaction of phenol is
2
C
6
H
5
O
H
⇌
(
C
6
H
5
O
H
)
2
Initial
concentration
C
0
After
dimerization
C
−
C
α
C
α
2
Here, C is the concentration of phenol:
C =
75.2
M
o
l
.
w
t
=
75.2
94
= 0.8
and α is the degree of dissociation. Then
i = C - Cα + Cα/2 =
C
(
2
−
α
)
2
Freezing point depression is given by
Δ
T
f
=
K
f
×
i
7 = 14 × 0.8 ×
(
2
−
α
2
)
α = 0.75 = 75%
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