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IIT JEE Advanced 2007 Paper 1
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© examsnet.com
Question : 19
Total: 66
The loss of kinetic energy during the above process is
I
ω
2
2
I
ω
2
3
I
ω
2
4
I
ω
2
6
Validate
Solution:
The total K.E. before merging the discs is
(
K
.
E
.
)
1
=
1
2
I
(
2
ω
)
2
+
1
2
2
I
ω
2
=
3
I
ω
2
The total K.E. after merger is
(
K
.
E
.
)
2
=
1
2
3
I
(
ω
′
)
2
=
8
3
I
ω
2
The change in kinetic energy is
(
K
.
E
.
)
2
-
(
K
.
E
.
)
1
=
8
3
I
ω
2
−
3
I
ω
2
= -
1
3
I
ω
2
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