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IIT JEE Advanced 2007 Paper 2
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© examsnet.com
Question : 6
Total: 66
A magnetic field
→
B
=
B
0
^
j
exists in the region a < x < 2a and
→
B
=
B
0
^
j
, in the region 2a < x < 3a, where
B
0
is a positive constant. A positive point charge moving with a velocity
→
v
=
v
0
^
i
, where
v
0
is a positive constant, enters the magnetic field at x = a. The trajectory of the charge in this region can be like,
Validate
Solution:
We know that
→
F
=
q
(
→
V
×
→
B
)
For a < x < 2a;
→
B
=
B
0
j
. Therefore,
→
F
1
= qvB(k)
Therefore, the path is circular and for 2a < x < 3a;
→
B
=
−
B
0
j
.
Therefore,
→
F
2
= - qvB(k)
and hence the path is circular and clockwise so the correct curve is the one shown in option (A).
© examsnet.com
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