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IIT JEE Advanced 2008 Paper 1

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In the following reaction sequence, products I, J and L are formed. K represents a reagent.

Section: Chemistry

Question : 40 of 69

Marks: +1, -0

Solution:

The formation of L takes place through the following Rosenmund reaction

\mathrm{CH_3-CH_2-C\equiv C-CH_2-CH_2-CO-Cl}

\xrightarrow[\text{Pd/BaSO}_4]{\mathrm{H}_2}

\mathrm{CH_3-CH_2-HC=CHCH_2C_2CHO}

(L)

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