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IIT JEE Advanced 2008 Paper 1
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© examsnet.com
Question : 5
Total: 69
Students I, II and III perform an experiment for measuring the acceleration due to gravity (g) using a simple pendulum. They use different lengths of the pendulum and/or record time for different number of oscillations. The observations are shown in the table.
Least count for length = 0.1 cm.
Least count for time = 0.1 s.
Student
Length of pendulum (cm)
Number of oscillations (n)
Total time for (n) oscillations (s)
Time period (s)
I
64.0
8
128.0
16.0
II
64.0
4
64.0
16.0
III
20.0
4
36.0
9.0
If
E
I
,
E
I
I
and
E
I
I
I
are the percentage errors in g, that is,
(
Δ
g
g
×
100
)
for students I, II, and III, respectively, then
E
1
= 0
E
1
is minimum
E
1
=
E
n
E
n
is maximum
Validate
Solution:
Student-I:
E
I
=
Δ
g
g
× 100 =
(
0.1
64.0
+
2
×
0.1
128
)
× 100 =
5
16
%
Student-II:
E
I
I
=
Δ
g
g
× 100 =
(
0.1
64.0
+
2
×
0.21
64
)
× 100 =
15
32
%
Student-III :
E
I
I
I
:
Δ
g
g
× 100 =
(
0.1
20.0
+
2
×
0.1
36
)
× 100 =
19
18
Therefore, the percentage error in g for
E
1
is minimum
© examsnet.com
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