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IIT JEE Advanced 2008 Paper 2
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© examsnet.com
Question : 1
Total: 66
A light beam is travelling from Region I to Region IV (refer to the figure). The refractive index in Regions I, II, III and IV are
n
0
,
n
0
6
,
n
0
6
and
n
0
8
, respectively. The angle of incidence θ for which the beam just misses entering Region IV is
s
i
n
−
1
(
3
4
)
s
i
n
−
1
(
1
8
)
s
i
n
−
1
(
1
4
)
s
i
n
−
1
(
1
3
)
Validate
Solution:
Let i be the angle of incidence at the interface of Region III and Region IV. Using shell’s law for Region I and Region III, we get
n
0
s
i
n
θ
=
n
0
6
s
i
n
i
For a total internal reflection in Region III, we have
i ≥
i
C
(Sin i) ≥
(
n
0
8
n
0
6
)
(sin i) ≥
(
3
4
)
Therefore,
n
0
s
i
n
θ
=
n
0
6
×
3
4
=
n
0
8
⇒ sin θ =
1
8
⇒ θ =
s
i
n
−
1
(
1
8
)
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