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IIT JEE Advanced 2008 Paper 2

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Question : 52

Total: 66

Consider a branch of the hyperbola x2−2y2−2√2x−4√2y−6 = 0 with vertex at the point A. Let B be one of the end points of its latus rectum. If C is the focus of the hyperbola nearest to the point A, then the area of the triangle ABC is

1−√
2
3
√
3
2
−1
1+√
2
3
√
3
2
+1

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