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IIT JEE Advanced 2008 Paper 2

Section: Physics

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Question : 6 of 66

Marks: +1, -0

A block (B) is attached to two up-stretched springs S1 and S2 with spring constants k and 4k, respectively (see the figure), the other ends are attached to identical supports M1 and M2 not attached to the walls. The springs and supports have negligible mass. There is no friction anywhere. The block B is displaced towards wall 1 by a small distance x (Figure II) and released. The block returns and moves a maximum distance y towards wall 2. Displacements x and y are measured with respect to the equilibrium position of the block B. The ratio y/x is

[JEE Adv 2008 P2]

4
2
1/2
1/4

Solution:

From conservation of energy, we have

\frac{1}{2} k x^2

=

\frac{1}{2} 4 k y^2

⇒

\frac{y}{x}

=

\frac{1}{2}

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