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IIT JEE Advanced 2009 Paper 1
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© examsnet.com
Question : 7
Total: 60
A ball is dropped from a height of 20 m above the surface of water in a lake. The refractive index of water is 4/3. A fish inside the lake, in the line of fall of the ball, is looking at the ball. At an instant, when the ball is 12.8 m above the water surface, the fish sees the speed of ball as (Take g = 10 m/
s
2
)
9 m/s
12 m/s
16 m/s
21.33 m/s
Validate
Solution:
The velocity of the ball when it has fallen through 7.2 m is
V =
√
2
g
(
7.2
)
= 12 m/s
For a general height h above the water surface, we have
h
′
h
=
4
3
⇒ h' =
4
3
h
Therefore, V; =
4
3
V
=
4
3
×
12
= 16 m/s
where V ′ is the velocity of ball with respect to the fish.
© examsnet.com
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