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IIT JEE Advanced 2009 Paper 2

Section: Chemistry

Question : 21 of 57

Marks: +1, -0

Cr(CO)_6

Solution:

[Cr(CO)_6]

: Cr(24) =

[Ar] 3d^5 4s^1

Since CO is a strong field ligand, so pairing of electrons will take place and the configuration will become

3d^6

. There will be no unpaired electrons, so, the spin only magnetic moment is zero.

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