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IIT JEE Advanced 2009 Paper 2
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© examsnet.com
Question : 3
Total: 57
The mass M shown in the figure below oscillates in simple harmonic motion with amplitude A. The amplitude of the point P is
k
1
A
k
2
k
2
A
k
1
k
1
A
k
1
+
k
2
k
2
A
k
1
+
k
2
Validate
Solution:
Since the restoring force is same in both springs (which are being in series), we have
k
1
x
1
=
k
2
x
2
It is given that
x
1
+
x
2
= A
⇒
x
1
=
A
k
2
k
1
+
k
2
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