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IIT JEE Advanced 2010 Paper 1
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© examsnet.com
Question : 1
Total: 84
Incandescent bulbs are designed by keeping in mind that the resistance of their filament increases with the increase in temperature. If at room temperature, 100, 60 and 40 W bulbs have filament resistances
R
100
,
R
60
and
R
40
respectively, the relation between these resistances is
1
R
100
=
1
R
40
+
1
R
60
R
100
=
R
40
+
R
60
R
100
>
R
40
>
R
60
1
R
100
>
1
R
40
>
1
R
60
Validate
Solution:
The power of the bulb is
P =
V
2
R
Therefore,
100 =
V
2
R
100
⇒
1
R
100
=
100
V
2
where
R
100
is the resistance (at any temperature) corresponds to 100 W. Similarly,
60 =
V
2
R
60
⇒
1
R
60
=
60
V
2
and 40 =
V
2
R
40
⇒
1
R
40
=
40
V
2
From these equations, we get
P
100
>
P
60
>
P
40
⇒
1
R
100
>
1
R
40
>
1
R
60
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