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IIT JEE Advanced 2010 Paper 1
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© examsnet.com
Question : 26
Total: 84
When two progressive waves
y
1
= 4sin(2x - 6t) and
y
2
= 3 sin
(
2
x
−
6
t
−
π
2
)
are superimposed, the amplitude of the resultant wave is _____.
Your Answer:
Validate
Solution:
The two waves are out of phase by π/2. Therefore, the resultant amplitude is
A
resultant
=
(
3
2
+
4
2
)
1
2
= 5
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