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IIT JEE Advanced 2011 Paper 1
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© examsnet.com
Question : 3
Total: 69
Consider an electric field
→
E
=
E
0
x
, where
E
0
is a constant. The flux through the shaded area (as shown in the figure) due to this field is
2
E
0
a
2
√
2
E
0
a
2
E
0
a
2
E
0
a
2
√
2
Validate
Solution:
Area of the shaded region is
a
2
^
x
. The flux is
ϕ =
→
E
. (Area) =
(
E
0
^
x
)
.
(
a
2
^
x
)
=
E
0
a
2
© examsnet.com
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