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IIT JEE Advanced 2011 Paper 1
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© examsnet.com
Question : 63
Total: 69
Consider the parabola
y
2
= 8x. Let Δ1 be the area of the triangle formed by the end points of its latus rectum and the point
P
(
1
2
,
2
)
on the parabola, and
Δ
2
be the area of the triangle formed by drawing tangents at P and at the end points of the latus rectum. Then
Δ
1
Δ
2
is ____.
Your Answer:
Validate
Solution:
The area of triangle formed by the three points on the parabola is twice the area of the triangle formed by the respective tangents.
That is,
ΔLPM = 2 × (Area of ΔABC)
y
2
= 8x = 4 × 2 × x
Δ
L
P
M
Δ
A
B
C
= 2
Δ
1
Δ
2
= 2
© examsnet.com
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