The equation of a plane passing through the line of intersection of the planes x + 2y + 3z = 2 and x – y + z = 3 and at a distance 2√3 from the point (3, 1, –1) is[JEE Adv 2012 P2]

Question

The equation of a plane passing through the line of intersection of the planes x + 2y + 3z = 2 and x – y + z = 3 and at a distance

2

√3

from the point (3, 1, –1) is

[JEE Adv 2012 P2]

Accepted Answer

Correct Answer is : 5x –11y + z = 17

Answer

5x –11y + z = 17

Answer

√2x+y = 3√2−1

Answer

x + y + z = √3

Answer

x−√2y = 1−√2

IIT JEE Advanced 2012 Paper 2