Let the initial position of the warship be A and initial and final positions of the submarine be P and Q respectively. AP =50km Ratio of speed of warship to submarine =2:1 ⇒AB=2PQ---------------Eqn(I) In ΔAPN ⇒sin‌30=
AN
AP
⇒
1
2
=
AN
50
⇒AN=
50
2
=25km ⇒BM=AN=50km Similarly PN=25√3=AR ∴ In ΔBMQ ⇒sin‌60=
BM
BQ
⇒
√3
2
=
25
BQ
⇒BQ=
50
√3
km Similarly MQ=
25
√3
Let RB = PM = x and using Eqn (I), we get : ⇒(AR+RB)=2(PM+MQ) ⇒(25√3+x)=2(x+