1/1·2·3+1/3·4·5+1/5·6·7+

Correct Answer is : None of the above

Correct Answer is : None of the above

Test Index

Indian Institute of Foreign Trade 2009 Solved Paper

Question : 97 of 122

Marks: +1, -0

\frac{1}{1\cdot2\cdot3}+\frac{1}{3\cdot4\cdot5}+\frac{1}{5\cdot6\cdot7}+\dots

Solution:

\frac{1}{1\cdot2\cdot3}+\frac{1}{3\cdot4\cdot5}+\frac{1}{5\cdot6\cdot7}+\dots 0.166+0.0166+0.00476\dots+\dots

which is always < 0.2 but a positive number.

Option A=

e^2-1=7.34-1=6.34

therefore this cannot be the Answer

Option B

=\log_e 2-1=\frac{\log_{10}2}{\log_{10}e}-1=\frac{\log_{10}2}{\log_{10}2.72-1}

We know that the value of

\frac{\log_{10}2}{\log_{10}2.72-1}

< 1 1 and therefore value of

\frac{\log_{10}2}{\log_{10}2.72}-1 < 0

therefore this cannot be the Answer

Option C

=2\log_{10}2-1=\log_{10}4-1

We know that the value of

\log_{10}4 < 1

and therefore value of

\log_{10}4-1 < 0

therefore this cannot be the Answer

Therefore the Answer is option 'D'

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