Let the interest on the second part be r%
Then, the rate on the first part
=(r+10) %It is given that,
(1+100)230000(r+10)​−(1+100)230000r​=7500On solving, we get r = 20%
Let the first part be Rs. a
Then, the second part =Rs. (60000-a)
a(1+100)220+10​−(6000−a)(1+100)220​=38800On solving, we get a = Rs. 40000
Hence, option C is the correct answer.