Hypotenuse = 97 m and perimeter = 234 m Let the other two sides be a m and b m So a+b=(234−97)m=137m....(i) Also, by Pythagoras Theorem,a2+b2=972 Or (a+b)2−2ab=9409 Or,2ab=1372−9409 Or,2ab=9360...(ii) (a−b)2=a2+b2−2ab=972+9360=49 So,(a−b)=7 [Assuming a > b]....(iii) Solving (i) and (iii), we get a =72 m and b = 65m Hence, option B is the correct answer.