Concept:Use substitution u=logx to convert the integral into a standard power integral.Explanation:Let I=∫xlogxdx.Set u=logx, then du=x1dx.Thus I=∫udu=2u2=2(logx)2.Evaluate from a to b: [2(logx)2]ab=21[(logb)2−(loga)2].Factor: (logb)2−(loga)2=(logb−loga)(logb+loga)=log(ab)⋅log(ba).Hence the integral equals 21log(ba)⋅log(ab).Answer:Option A: 21log(ba)⋅log(ab).