IPMAT 2025 Exam Solved Papers

The amount invested in Scheme A is 30,000. Let the amount invested in scheme B be X, and the amount invested in scheme C be 70000 - X. The interest rates in scheme A, scheme B, and scheme C are 10%, 8%, and 12%, compounded annually.Now, since in the first year, the amount of simple interest is the same as the amount of compound interest, we will use the formulas of simple interest for the first year for calculations.It is given that the total interest earned from all three schemes during the first year is 10600.$$\begin{aligned} & \Rightarrow \frac{30000 \times 10 \times 1}{100}+\frac{X \times 8 \times 1}{100}+\frac{(70000-X) \times 12 \times 1}{100}=10600 \\ & \Rightarrow 3000+\frac{8 X}{100}+8400-\frac{12 X}{100}=10600 \end{aligned}$$$$\begin{aligned} & \Rightarrow \frac{4 X}{100}=800 \\ & \Rightarrow X=20000 \end{aligned}$$Thus, the amount invested in scheme B is 20,000, and the amount invested in scheme C is 50,000.The total amount at the end of 2 years will be $30000(1.1)^{2}+20000(1.08)^{2}+50000(1.12)^{2}$The total amount at the end of 2 years will be $36300+23328+62720=122348$Thus, the interest earned in the 2 years will be $=122348-100000=22348$Now, the interest earned in the first year was 10600. Thus, the interest earned in the second year will be equal to the total interest earned over the two years minus the interest earned in the first year.Thus, the interest earned in the second year will be $=22348-10600=11748$ Rupees.