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JEE Advanced 2013 Paper 1
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© examsnet.com
Question : 14
Total: 60
A particle of mass M and positive charge Q, moving with a constant velocity
→
u
1
=
4
^
i
ms
−
1
,
enters a region of uniform static magnetic field normal to the x-y plane. The region of the magnetic field extends from x = 0 to x = L for all values of y. After passing through this region, the particle emerges on the other side after 10 milliseconds with a velocity
→
u
2
=
2
(
√
3
^
i
+
^
j
)
ms
−
1
.The correct statement(s) is (are):
The direction of the magnetic field is -z direction.
The direction of the magnetic field is +z direction
The magnitude of the magnetic fieId
50
M
π
3
Q
units
The magnitude of the magnetic field is
100
π
M
3
Q
units
Validate
Solution:
So magnetic field is along -ve, z-direction.
Time taken in the magnetic field =
10
×
10
−
3
=
π
M
6
Q
B
B
=
π
M
60
×
10
−
3
Q
=
1000
π
M
60
Q
=
50
π
M
3
Q
© examsnet.com
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