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JEE Advanced 2013 Paper 2
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© examsnet.com
Question : 1
Total: 60
Two bodies, each of mass M, are kept fixed with a separation 2L. A particle of mass m is projected from the midpoint of the line joining their centres,perpendicular to the line. The gravitational constant is G. The correct statement(s) is (are):
The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is 4
√
G
M
L
The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is 2
√
G
M
L
The minimum initial velocity of the mass m to escape the gravitational field of the two bodies is
√
2
G
M
L
The energy of the mass m remains constant
Validate
Solution:
1
2
m
v
min
2
+
m
[
−
GM
L
×
2
]
=
0
energy conservation
v
min
2
2
=
2
GM
L
v
min
=
2
√
GM
L
as (B)
Total energy of mass does not remain constant as net force on it is non-zero
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