One mole of a monatomic ideal gas is taken along two cyclic processes E → F → G → E and E → F → H → E as shown in the PV diagram. The processes involved are purely isochoric, isobatic, isothermal or adiabatic. Match the paths in List I with the magnitudes of the work done in List II and select the correct answer using the codes given below the lists. List I List II P. G → E 1. 160 P₀ V₀ ln2 Q. G → H 2. 36 P₀ V₀ R. F → H 3. 24 P₀ V₀ S. F → G 4. 31P₀ V₀ [JEE Adv 2013 P2]

Question

One mole of a monatomic ideal gas is taken along two cyclic processes E → F → G → E and E → F → H → E as shown in the PV diagram. The processes involved are purely isochoric, isobatic, isothermal or adiabatic. Match the paths in List I with the magnitudes of the work done in List II and select the correct answer using the codes given below the lists. List I List II P. G → E 1. 160 P₀ V₀ ln2 Q. G → H 2. 36 P₀ V₀ R. F → H 3. 24 P₀ V₀ S. F → G 4. 31P₀ V₀ [JEE Adv 2013 P2]

Examsnet · Accepted Answer

Correct Answer is : P-4 Q-3 R-2 S-1

List I	List II
P. G → E	1. 160 $P_0 V_0$ ln2
Q. G → H	2. 36 $P_0 V_0$
R. F → H	3. 24 $P_0 V_0$
S. F → G	4. 31 $P_0 V_0$

JEE Advanced 2013 Paper 2