Test Index

JEE Advanced 2013 Paper 2

Show Para Hide Para

Paragraph for Next 2 Questions

Let S = S

\_1

∩ S

\_2

∩ S

\_3

S

\_1

= {z ∊ C : |z| < 4}, S

\_2

=

\{z \in C : lm\left[\frac{z-1+\sqrt{3}i}{1-\sqrt{3}i}\right] > 0\}

and

S

\_3

: {z ∊ C : Re z > 0}

Section: Mathematics

© examsnet.com

Question : 53 of 60

Marks: +1, -0

Area of S =

[JEE Adv 2013 P2]

$\frac{10\pi}{3}$
$\frac{20\pi}{3}$
$\frac{16\pi}{3}$
$\frac{32\pi}{3}$

Solution:

Area of region

S_1

∩

S_2

∩

S_3

= shaded area

=

\frac{\pi \times 4^2}{4} + \frac{4^2 \times \pi}{6}

=

4^2 \pi \left( \frac{1}{4} + \frac{1}{6} \right)

=

\frac{20\pi}{3}

© examsnet.com

Go to Question:

Prev Question

Next Question