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JEE Advanced 2013 Paper 2
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© examsnet.com
Question : 6
Total: 60
Two non-conducting spheres of radii
R
1
and
R
2
and carrying uniform volume charge densities +ρ and -ρ, respectively, are placed such that they partially overlap, as shown in figure. At all points in the overlapping region :
the electrostatic field is zero
the electrostatic potential is constant
the electrostatic field is constant in magnitude
the electrostatic field has same direction
Validate
Solution:
In triangle
P
C
1
C
2
→
r
2
=
→
d
+
→
r
1
The electrostatic field at point P is
→
E
=
K
(
ρ
4
3
π
R
1
3
)
→
r
2
R
1
3
+
K
(
ρ
4
3
π
R
2
3
)
(
−
→
r
2
)
R
2
3
→
E
=
K
ρ
4
3
π
(
→
r
2
−
→
r
1
)
→
E
=
ρ
3
ε
0
→
d
© examsnet.com
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